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36n^2-54n+8=0
a = 36; b = -54; c = +8;
Δ = b2-4ac
Δ = -542-4·36·8
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-42}{2*36}=\frac{12}{72} =1/6 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+42}{2*36}=\frac{96}{72} =1+1/3 $
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